Advertisement Remove all ads

In the Following, Determine Whether the Given Quadratic Equation Have Real Roots and If So, Find the Roots: 16x2 = 24x + 1 - Mathematics

In the following, determine whether the given quadratic equation have real roots and if so, find the roots:

16x2 = 24x + 1

Advertisement Remove all ads

Solution

We have been given,

16x2 = 24x + 1

16x2 - 24x - 1 = 0

Now we also know that for an equation ax2 + bx + c = 0, the discriminant is given by the following equation:

D = b2 - 4ac

Now, according to the equation given to us, we have,a = 16, b = -24 and c = -1.

Therefore, the discriminant is given as,

D = (-24)2 - 4(16)(-1)

= 576 + 64

= 640

Since, in order for a quadratic equation to have real roots, D ≥ 0.Here we find that the equation satisfies this condition, hence it has real roots.

Now, the roots of an equation is given by the following equation,

`x=(-b+-sqrtD)/(2a)`

Therefore, the roots of the equation are given as follows,

`x=(-(-24)+-sqrt640)/(2(16))`

`=(24+-8sqrt10)/32`

`=(3+-sqrt10)/4`

Now we solve both cases for the two values of x. So, we have,

`x=(3+sqrt10)/4`

Also,

`x=(3-sqrt10)/4`

Therefore, the roots of the equation are `(3+sqrt10)/4`and `(3-sqrt10)/4`

Concept: Relationship Between Discriminant and Nature of Roots
  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

RD Sharma Class 10 Maths
Chapter 4 Quadratic Equations
Exercise 4.5 | Q 2.01 | Page 32
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×