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In the Following Determine the Set of Values of K for Which the Given Quadratic Equation Has Real Roots: Kx2 + 6x + 1 = 0 - Mathematics

In the following determine the set of values of k for which the given quadratic equation has real roots:

kx2 + 6x + 1 = 0

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Solution

The given quadric equation is kx2 + 6x + 1 = 0, and roots are real

Then find the value of k.

Here, a = k, b = 6 and c = 1

As we know that D = b2 - 4ac

Putting the value of a = k, b = 6 and c = 1

= 62 - 4 x (k) x (1)

= 36 - 4k

The given equation will have real roots, if D ≥ 0

36 - 4k ≥ 0

4k ≤ 36

k ≤ 36/4

k ≤ 9

Therefore, the value of k ≤ 9.

  Is there an error in this question or solution?
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APPEARS IN

RD Sharma Class 10 Maths
Chapter 4 Quadratic Equations
Exercise 4.6 | Q 3.4 | Page 42
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