In the figure shown, an ammeter A and a resistor of 4 Ω are connected to the terminals of the source. The emf of the source is 12 V having an internal resistance of 2 Ω. Calculate the voltmeter and ammeter readings.
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Solution
Considering voltmeter and ammeter to be ideal. Then
Ammeter reading will be,
`I = 12/(4 + 2)`
`= 2 A`
Voltmeter reading will be,
V = 12 − I × 2
= 12 − 2 × 2
=8 V
Concept: Electric Potential Difference
Is there an error in this question or solution?
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