In figure PA and PB are tangents from an external point P to the circle with centre O. LN touches the circle at M. Prove that PL + LM = PN + MN
Advertisement Remove all ads
Solution
Given
O is Centre of circle
PA and PB are tangents
We know that
The tangents drawn from external point to the circle are equal in length.
From point P, PA = PB
⇒ PL + AL = PN + NB …. (i)
From point L & N, AL = LM and MN = NB } …. Substitute in (i)
PL + Lm = PN + MN
⇒ Hence proved.
Concept: Concept of Circle - Centre, Radius, Diameter, Arc, Sector, Chord, Segment, Semicircle, Circumference, Interior and Exterior, Concentric Circles
Is there an error in this question or solution?
APPEARS IN
Advertisement Remove all ads
