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Sum
In figure, if ∠D = ∠C, then it is true that ΔADE ~ ΔACB? Why?
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Solution
True
In ΔADE and ΔACB,
∠A = ∠A ....[Common angle]
∠D = ∠C ......[Given]
ΔADE ~ ΔACB .....[By AAA similarity criterion]
Concept: Similarity of Triangles
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