Sum
In figure, if ∠A = ∠C, then prove that ∆AOB ~ ∆COD
Advertisement Remove all ads
Solution
In triangles AOB and COD, we have
∠A = ∠C [Given] and, ∠1 = ∠2 [Vertically opposite angles]
Therefore, by AA-criterion of similarity, we have
∆AOB ~ ∆COD
Concept: Similarity
Is there an error in this question or solution?
Advertisement Remove all ads
Advertisement Remove all ads