In figure, common tangents AB and CD to two circles intersect at E. Prove that AB = CD.
Given: AB and CD are two tangents to two circles which intersects at E.
To Prove: AB = CD
AE = CE ......[Tangents drawn from an external point to a circle are equal] 
EB = ED ......[Tangents drawn from an external point to a circle are equal] 
Adding  and 
AE + EB = CE + ED
AB = CD
Concept: Number of Tangents from a Point on a Circle
Is there an error in this question or solution?