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Sum

In figure, arcs are drawn by taking vertices A, B and C of an equilateral triangle of side 10 cm. to intersect the sides BC, CA and AB at their respective mid-points D, E and F. Find the area of the shaded region (Use π = 3.14).

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#### Solution

ABC is an equilateral triangle.

And, AB = BC = CA = 10 cm

As, D, E, F are mid-points of the sides,

AE = EC = CD = BD = BF = FA = 5 cm

∠A = ∠B = ∠C = 60°

Area of sector CDE = `theta/360 xx pir^2`

= `60/360 xx pi (5)^2`

= 13.0833 cm^{2}

Area of shaded region = 3 × Area of sector CDE

= 3× 13.0833

= 39.25 cm^{2}

Concept: Areas of Combinations of Plane Figures

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