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# In Figure, ABC and DBC are two triangles on the same base BC. If AD intersects BC at O, show that (ar(ABC))/(ar(DBC)) = (AO)/(DO) - Mathematics

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#### Question

In Figure, ABC and DBC are two triangles on the same base BC. If AD intersects BC at O, show that (ar(ABC))/(ar(DBC)) = (AO)/(DO) #### Solution

Let us draw two perpendiculars AP and DM on line BC. We know that area of a triangle = 1/2 x Base x Height

:.(ar(triangleABC))/(ar(triangleDBC)) =  (1/2 BC XX AP)/(1/2BCxxDM)) = (AP)/(DM)

In ΔAPO and ΔDMO,

∠APO = ∠DMO (Each = 90°)

∠AOP = ∠DOM (Vertically opposite angles)

∴ ΔAPO ∼ ΔDMO (By AA similarity criterion)

:. (AP)/(DM) = (AO)/(DO)

=> (ar(triangleABC))/(ar(triangleDBC))=(AO)/(DO)

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#### APPEARS IN

NCERT Solution for Mathematics Textbook for Class 10 (2019 (Latest))
Chapter 6: Triangles
Ex. 6.4 | Q: 3 | Page no. 144
RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 7: Triangles
Ex. 7.6 | Q: 19 | Page no. 96
RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 7: Triangles
Ex. 7.6 | Q: 19 | Page no. 96

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Solution In Figure, ABC and DBC are two triangles on the same base BC. If AD intersects BC at O, show that (ar(ABC))/(ar(DBC)) = (AO)/(DO) Concept: Areas of Similar Triangles.
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