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In Figure 1, PS = 3 cm, QS = 4 cm, ∠PRQ = θ, ∠PSQ = 90°, PQ ⊥ RQ and RQ = 9 cm. Evaluate tan θ. - Mathematics

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Sum

In Figure 1, PS = 3 cm, QS = 4 cm, ∠PRQ = θ, ∠PSQ = 90°, PQ ⊥ RQ and RQ = 9 cm. Evaluate tan θ.

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Solution

Given,
PS = 3 cm, QS = 4 cm, RQ = 9cm

In In ΔPSQ,
PQ2 =PS2 + OS2

PQ2 = 32 +42 = 25 

⇒ PQ = 5 cm

In Δ PQR,

tan θ =`"PQ"/"RQ"`
⇒ tan θ =`5/9`

Concept: Area of a Triangle
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