Sum

In Figure 1, PS = 3 cm, QS = 4 cm, ∠PRQ = θ, ∠PSQ = 90°, PQ ⊥ RQ and RQ = 9 cm. Evaluate tan θ.

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#### Solution

Given,

PS = 3 cm, QS = 4 cm, RQ = 9cm

In In ΔPSQ,

PQ^{2} =PS^{2} + OS^{2}

PQ^{2} = 3^{2} +4^{2} = 25

⇒ PQ = 5 cm

In Δ PQR,

tan θ =`"PQ"/"RQ"`

⇒ tan θ =`5/9`

Concept: Area of a Triangle

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