Answer 1

We know that the tangents drawn from any external point to circle are equal in length.

From A ⟶ AS = AP ….(i)

From B ⟶ QB = BP …. (ii)

From C ⟶ QC = RC …..(iii)

From D ⟶ DS = DR …. (iv)

Adding (i), (ii), (iii) & (iv)

(AS + QB + QC + DS) = (AB + BP + RC + OR)

(AS + DS) + (QB + QC) = (AP + BP) + (RC + DR)

AD + BC = AB + CD

⇒ AD + 7 = 6 + 4       AD = 3cm

⇒ AD = 10 – 7 = 3cm