#### Question

In Fig. 3, APB and AQO are semicircles, and AO = OB. If the perimeter of the figure is 40 cm, find the area of the shaded region [Use `pi=22/7`]

#### Solution

Let the radius of the semi-circle APB be *r*

⇒ The radius of the semi-circle AQO =`r/2`

Now,

Perimeter of the given figure *= *Length of arc AQO + Length of arc APB + OB

`=pixxr/2+pixxr+r`

`=r(3/2pi+1)`

`=r(3/2xx22/7+1)`

`= r((33+7)/7)`

`=r(40/7)cm`

⇒r=7 cm

∴ Area of the shaded region = Area of semi-circle AQO + Area of semi-circle APB

`=(pi(r/2)^2)/2+(pir^2)/2`

`=(pi(7/2)^2)/2+(pixx7^2)/2`

`=(49pi)/8+(49pi)/2`

`=49pi(1/8+1/2)`

`=49xx22/7xx5/8`

= 96.25 cm^{2}

Is there an error in this question or solution?

Solution In Fig. 3, APB and AQO are semicircles, and AO = OB. If the perimeter of the figure is 40 cm, find the area of the shaded region Concept: Problems Based on Areas and Perimeter Or Circumference of Circle, Sector and Segment of a Circle.