Question
In each of the following find the value of 'k', for which the points are collinear.
(7, -2), (5, 1), (3, -k)
Solution
For collinear points, area of triangle formed by them is zero.
Therefore, for points (7, -2) (5, 1), and (3, k), area = 0
`1/2 [7 { 1- k} + 5(k-(-2)) + 3{(-2) + 1}] = 0`
7 - 7k + 5k +10 -9 = 0
-2k + 8 = 0
k = 4
Is there an error in this question or solution?
Solution In Each of the Following Find the Value of 'K', for Which the Points Are Collinear. (7, -2), (5, 1), (3, -k) Concept: Area of a Triangle.
