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In Each of the Following Find the Value of 'K', for Which the Points Are Collinear. (7, -2), (5, 1), (3, -k) - Mathematics

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In each of the following find the value of 'k', for which the points are collinear.

(7, -2), (5, 1), (3, -k

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Solution

For collinear points, area of triangle formed by them is zero.

Therefore, for points (7, -2) (5, 1), and (3, k), area = 0

`1/2 [7 { 1- k} + 5(k-(-2)) + 3{(-2) + 1}] = 0`

7 - 7k + 5k +10 -9 = 0

-2k + 8 = 0

k = 4

Concept: Area of a Triangle
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APPEARS IN

NCERT Class 10 Maths
Chapter 7 Coordinate Geometry
Exercise 7.3 | Q 2.1 | Page 170
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