SSC (English Medium) Class 8Maharashtra State Board
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# In Each Example Given Below, Radius of Base of a Cylinder and Its Height Are Given. Then Find the Curved Surface Area and Total Surface Area. - SSC (English Medium) Class 8 - Mathematics

ConceptSurface Area of Cylinder

#### Question

In each example given below, radius of base of a cylinder and its height are given. Then find the curved surface area and total surface area.
(1) r = 7 cm, h = 10 cm
(2) r = 1.4 cm, h = 2.1 cm
(3) r = 2.5 cm, h = 7 cm
(4) r = 70 cm, h = 1.4 cm
(5) r = 4.2 cm, h = 14 cm

#### Solution

We know that
Curved surface area of a cylinder = 2 π rh
Total surface area = 2 πr (h + r)

(1) r = 7 cm, h = 10 cm
Curved surface area of a cylinder = 2 π rh = 2 π × 7 × 10 = 140 π = 140 × 22/7 = 440 sq cm

Total surface area = 2 π r (h + r) = 2 × 22/7 (10 + 7) = 748 sq cm

(2) r = 1.4 cm, h = 2.1 cm
Curved surface area of a cylinder = 2 π rh = 2 × 22/7 × 1.4 × 2.1 = 18.48 sq cm

Total surface area = 2 π r (h + r) = 2 × 22/7 ×1.4 (2.1 + 1.4) = 30.8 sq cm

(3) r = 2.5 cm, h = 7 cm
Curved surface area of a cylinder = 2 π rh = 2 × 22/7 × 2.5× 7 = 110 sq cm

Total surface area = 2 π r (h + r) = 2 × 22/7 × 2.5 (2.5 + 7) = 149.28 sq cm

(4) r = 70 cm, h = 1.4 cm
Curved surface area of a cylinder = 2 π rh = 2 × 22/7 × 70 × 1.4 = 616 sq cm

Total surface area = 2 π r (h + r) = 2 × 22/7 × 70  (70  + 1.4) = 31416 sq cm

(5) r = 4.2 cm, h = 14 cm
Curved surface area of a cylinder = 2 π rh = 2 × 22/7 × 4.2 × 14 = 369.6 sq cm

Total surface area = 2 π r (h + r) = 2 × 22/7 × 4.2  (4.2  + 1.4) = 480.48 sq cm

Is there an error in this question or solution?

#### APPEARS IN

Balbharati Solution for Balbharati Class 8 Mathematics (2019 to Current)
Chapter 16: Surface area and Volume
Practice Set 16.2 | Q: 1 | Page no. 110
Solution In Each Example Given Below, Radius of Base of a Cylinder and Its Height Are Given. Then Find the Curved Surface Area and Total Surface Area. Concept: Surface Area of Cylinder.
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