Question

In a cyclotron, magnetic field of 3·5Wb/m2 is used to accelerate protons. What should be the time interval in which the electric field between the Dees be reversed?
(Mass of proton = 1· 67 x 10^-27Kg, Charge on proton =1·6x10^-19c).

Answer 1

B = 3.5 Wb/m² , m_P = 1.67 × 10^-27 Kg,

e = 1.6 × 10^-19 C,

t = ?

t = `pi"m"_"P"/"Bq"_"p"`

 

t = `(3.142 xx 1.67 xx 10^-27)/(3.5 xx 1.6 xx 10^-19)`

`= (3.142 xx 1.67)/(3.5 xx 1.6) xx 10^-8`

= [log (3.142) + log (1.67) - log (3.5) - log (1.6)] × 10^-8

= [0.4972 + 0.2227 - 0.5441 - 0.2041] × 10^-8 

= [antilog (- 0.0283)] × 10^-8 s

= 0.9369 × 10^-8 s

= 9.369 × 10^-9 s

The dees should be reversed within time interval of 9.369 × 10^-9 S.