Answer 1

It is given that

ABCD is cyclic quadrilateral and   ` m angle A = 3 (m  angle C ) `

We have to find  `m angle A `

Since ABCD is cyclic quadrilateral and sum of opposite pair of cyclic quadrilateral is 180°.

So ` angle A + angle C = 180°`

And

`3angleC + angleC = 180°`

              `4angleC = 180°`

           `angleC = (180°)/4`

                        = 45° 

Therefore

`angleA = 3 xx 45° `

              = 135° 

Hence  `angle A = 135°`