Short Note

In a cyclic quadrilateral *ABCD*, if *m *∠*A* = 3 (*m* ∠*C*). Find *m* ∠*A*.

Advertisement Remove all ads

#### Solution

It is given that

*ABCD* is cyclic quadrilateral and ` m angle A = 3 (m angle C ) `

We have to find `m angle A `

Since *ABCD* is cyclic quadrilateral and sum of opposite pair of cyclic quadrilateral is 180°.

So ` angle A + angle C = 180°`

And

`3angleC + angleC = 180°`

`4angleC = 180°`

`angleC = (180°)/4`

= 45°

Therefore

`angleA = 3 xx 45° `

= 135°

Hence `angle A = 135°`

Is there an error in this question or solution?

Advertisement Remove all ads

#### APPEARS IN

Advertisement Remove all ads

Advertisement Remove all ads