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Question
In copper, each copper atom releases one electron. If a current of 1.1 A is flowing in the copper wire of uniform cross-sectional area of diameter 1 mm, then drift velocity of electrons will approximately be: (Density of copper = 9 × 103 kg /m3, Atomic weight of copper = 63)
Options
10.3 mm/s
0.1 mm/s
0.2 mm/s
0.2 cm/s
MCQ
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Solution
0.1 mm/s
Explanation:
Given I = 1.1 A
e = 1.6 × 10-19 C
A = πr2 = π × (0.5 × 10–3)2 cm2
Electron density n
= `("N"_"A"rho)/"M"`
= `((6.023xx10^2)^3(9xx10^3))/(63xx10^-3)`
= 0.86 × 1029 m-3
Drift velocity vd = `1/"neA"`
vd = `1.1/(0.86xx10^29xx1.6xx10^-19 xxpi(0.5xx10^-3)^2)`
vd = 0.1 × 10-3 m/s
= 0.1 mm/s
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