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In the Below Fig, P is a Transversal to Lines M and N,`∠`2 = 120° and `A∠`5 = 60°. Prove that M || N. - Mathematics

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In the below fig, p is a transversal to lines m and n,`∠`2 = 120° and `a∠`5 = 60°. Prove that m || n.

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Solution

Given that

`∠`2 = 120°, `∠`5 = 60°

To prove

`∠`2 + `∠`1 = 180°            [ ∵ Linear pair]

120° + `∠`1 = 180°

`∠`1 = 180° -120°

`∠`1 = 60°

Since `∠`1 = `∠`5 = 60°

∴ m || n   [As pair of corresponding angles are equal]

 

 

Concept: Parallel Lines and a Transversal
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APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 10 Lines and Angles
Exercise 10.4 | Q 14 | Page 47

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