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In the Below Fig. D and E Are Two Points on Bc Such that Bd = De = Ec. Show that Ar (δAbd) = Ar (δAde) = Ar (δAec). - Mathematics

In the below fig. D and E are two points on BC such that BD = DE = EC. Show that ar
(ΔABD) = ar (ΔADE) = ar (ΔAEC).

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Solution

Draw a line through A parallel to BC

Given that, BD= DE = EC
We observe that the triangles ABD and AEC are on the equal bases and between the same
parallels C and BC. Therefore, Their areas are equal.
Hence, ar ( ABD) = ar (ΔADE) = ar ( ΔACDE)

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APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 14 Areas of Parallelograms and Triangles
Exercise 14.3 | Q 15 | Page 46
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