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In an AP
Given a12 = 37, d = 3, find a and S12.
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Solution
Given that, a12 = 37, d = 3
As an = a + (n − 1)d,
a12 = a + (12 − 1)3
37 = a + 33
a = 4
`S_n = n/2[a+a_n]`
`S_n = 12/2[4+37]`
`S_n = 6(41)`
`S_n = 246`
Concept: Sum of First n Terms of an A.P.
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