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In an AP Given a12 = 37, d = 3, find a and S12. - Mathematics

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 In an AP

Given a12 = 37, d = 3, find a and S12.

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Solution

Given that, a12 = 37, d = 3

As an = a + (n − 1)d,

a12 = a + (12 − 1)3

37 = a + 33

a = 4

`S_n = n/2[a+a_n]`

`S_n = 12/2[4+37]`

`S_n = 6(41)`

`S_n = 246`

Concept: Sum of First n Terms of an AP
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APPEARS IN

NCERT Class 10 Maths
Chapter 5 Arithmetic Progressions
Exercise 5.3 | Q 3.03 | Page 112
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