Answer 1

In the given problem, we have the first and the nth term of an A.P. along with the sum of the n terms of A.P. Here, we need to find the number of terms and the common difference of the A.P.

Here,

The first term of the A.P (a) = 22

The nth term of the A.P (l) = −11

Sum of all the terms S_n = 66 

Let the common difference of the A.P. be d.

So, let us first find the number of the terms (n) using the formula,

      `66 = (n/2) [ 22 + (-11)]`

      `66 = (n/2 ) (22 - 11)`

( 66)(2) = (n)(11)

Further, solving for n

`n =( (66)(2))/11`

n = (6) (2) 

n = 12

Now, to find the common difference of the A.P. we use the following formula,

l = a + ( n-1) d

We get,

             -11 = 22 + ( 12 - 1) d

             - 11 = 22 + ( 11) d

`(-11 - 22) /11 = d`

Further, solving for d,

`d =( -33)/11`

d = -3

Therefore, the number of terms is n = 12  and the common difference of the A.P.d = -3 .