Question

In an examination, a student has to answer 4 questions out of 5 questions; questions 1 and 2 are however compulsory. Determine the number of ways in which the student can make the choice.

Answer 1

Given that question number 1 and 2 are compulsory

∴ The remaining questions are 5 – 2 = 3

Total number of questions to be attempted = 4 questions 1 and 2 are compulsory

So only 2 questions are to be done out of 3 questions

Therefore number of ways = ³C₂

= ³C_3–2

= 3  ......`[∴ ""^nC_r = ""^nC_(n - r)]`

Hence, the required number of ways = 3.