# In an examination, a student has to answer 4 questions out of 5 questions; questions 1 and 2 are however compulsory. Determine the number of ways in which the student can make the choice. - Mathematics

Sum

In an examination, a student has to answer 4 questions out of 5 questions; questions 1 and 2 are however compulsory. Determine the number of ways in which the student can make the choice.

#### Solution

Given that question number 1 and 2 are compulsory

∴ The remaining questions are 5 – 2 = 3

Total number of questions to be attempted = 4 questions 1 and 2 are compulsory

So only 2 questions are to be done out of 3 questions

Therefore number of ways = 3C2

= 3C3–2

= 3  ......[∴ ""^nC_r = ""^nC_(n - r)]

Hence, the required number of ways = 3.

Concept: Combination
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Chapter 7: Permutations and Combinations - Exercise [Page 123]

#### APPEARS IN

NCERT Exemplar Class 11 Mathematics
Chapter 7 Permutations and Combinations
Exercise | Q 19 | Page 123

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