# In an A.P. a = 2 and d = 3, then find S12 - Algebra

Sum

In an A.P. a = 2 and d = 3, then find S12

#### Solution

a = 2 and d = 3   ......[Given]

Since Sn = "n"/2 [2"a" + ("n" - 1)"d"],

S12 = 12/2 [2(2) + (12 - 1)(3)]

= 6[4 + 11(3)]

= 6(4 + 33)

= 6(37)

= 222

Concept: Sum of First n Terms of an AP
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