Sum
In an A.P., a = 10 and d = −3 then find its first four terms
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Solution
a = 10, d = – 3 ......[Given]
t1 = a = 10
t2 = t1 + d = 10 – 3 = 7
t3 = t2 + d = 7 – 3 = 4
t4 = t3 + d = 4 – 3 = 1
∴ The first four terms of A.P. are 10, 7, 4, 1.
Concept: Arithmetic Progression
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