Department of Pre-University Education, Karnataka course PUC Karnataka Science Class 12
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In an Agricultural Experiment, a Solution Containing 1 Mole of a Radioactive Material (T1/2= 14.3 Days) Was Injected into the Roots of a Plant. the Plant Was Allowed 70 Hours to Settle Down and - Physics

Question

In an agricultural experiment, a solution containing 1 mole of a radioactive material (t1/2= 14.3 days) was injected into the roots of a plant. The plant was allowed 70 hours to settle down and then activity was measured in its fruit. If the activity measured was 1 µCi, what per cent of activity is transmitted from the root to the fruit in steady state?

Solution

Given:
Initial no of atoms, N0 = 1 mole = 6 × 1023 atoms
Half-life of the radioactive material, T1/2 = 14.3 days
Time taken by the plant to settle down, t = 70 h

Disintegration constant, lambda = 0.693/t_"1/2" = 0.693/(14.3 xx 24) "h"^-1

N = N_0e^(-lambdat)

= 6 xx 10^23 xx e^((-0.693 xx 70)/(14.3 xx 24))

= 6 xx 10^23 xx 0.868

= 5.209 xx 10^23

Activity , R = "dN"/"dt" = 5.209 xx 10^23 xx 0.693/(14.3 xx 24)

= (0.0105 xx 10^23)/3600 "dis/hr"

= 2.9 xx 10^-6 xx 10^23  "dis/sec"

= 2.9 xx 10^17 "dis/sec"

Fraction of activity transmitted = ((1 µCi)/(2.9 xx 10^17)) xx 100%

= [((1 xx 3.7 xx 10^4)/(2.9 xx 10^17)) xx 100%]

= 1.275 xx 10^-11 %

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Solution In an Agricultural Experiment, a Solution Containing 1 Mole of a Radioactive Material (T1/2= 14.3 Days) Was Injected into the Roots of a Plant. the Plant Was Allowed 70 Hours to Settle Down and Concept: Radioactivity - Introduction of Radioactivity.
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