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In the adjoining figure, ΔABC is right-angled at B and ∠A = 30^{0}. If BC = 6cm, find (i) AB, (ii) AC.

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#### Solution

From the given right-angled triangle, we have:

`(BC)/(AB)= tan 30^0`

⇒`6/(AB) = 1/sqrt(3)`

⇒ `AB = 6 sqrt(3) cm`

Also, `(BC)/(AC) = sin 30^0`

⇒`6/(AC)=1/2`

⇒ `AC = (2xx6)=12 cm `

∴ AB = 6`sqrt(3)` cm and AC = 12 cm

Concept: Trigonometric Ratios and Its Reciprocal

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