#### Question

In ΔABC and ΔDEF, it is being given that: AB = 5 cm, BC = 4 cm and CA = 4.2 cm; DE=10cm, EF = 8 cm and FD = 8.4 cm. If AL ⊥ BC and DM ⊥ EF, find AL: DM.

#### Solution

Since, `"AB"/"DE"="BC"/"EF"="AC"/"DE"=1/2`

Then, ΔABC ~ ΔDEF [By SSS similarity]

Now, In ΔABL ~ ΔDEM

∠B = ∠E [Δ ABC ~ ΔDEF]

∠ALB = ∠DME [Each 90°]

Then, ΔABL ~ ΔDEM [By AA similarity]

`therefore"AB"/"DE"="AL"/"DM"` [Corresponding parts of similar Δ are proportional]

`rArr5/10="AL"/"DM"`

`rArr1/2="AL"/"DM"`

Is there an error in this question or solution?

#### APPEARS IN

Solution In triangle Abc and triangle Def, It is Being Given That: Ab = 5 Cm, Bc = 4 Cm and Ca = 4.2 Cm; De=10cm, Ef = 8 Cm and Fd = 8.4 Cm. If Al ⊥ Bc and Dm ⊥ Ef, Find Al: Dm. Concept: Similarity Examples and Solutions.