A potentionmeter wire has resistance of per unit length of 0.1 Ω/m. A cell of e.m.f. 1.5V balances against 300 cm length of the wire. Find the current in the potentiometer wire.

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#### Solution

Given:- σ = 0.1 Ω/m, E = 1.5 V,

L = 300 cm = 3 m.

To find:- Current through potentiometer (I).

Formulae: i. σ = R/L ii. I = E/R

Calculation:- From formula (i),

R = σL

= 0.1 x 3 = 0.3 Ω

From formula (ii),

I = 1.5/0.3 = 5 A

**Current through the potentiometer wire is 5 A.**

Concept: Potentiometer

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