In a ∆ABC, ∠A = 90°, AB = 5 cm and AC = 12 cm. If AD ⊥ BC, then AD =
Given: In ΔABC, `∠ A = 90^o` AD ⊥ BC, AC = 12cm, and AB = 5cm.
To find: AD
We know that the ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding sides.
In ∆ACB and ∆ADC,
We got the result as `b`.
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