In a right angled triangle, if length of hypotenuse is 25 cm and height is 7 cm, then what is the length of its base?
Let ∆ABC be the given right angled triangle.
AC = 25 cm, AB = 7 cm
In ∆ABC, ∠B = 90° ......[Given]
∴ AC2 = AB2 + BC2 .......[Pythagoras theorem]
∴ 252 = 72 + BC2
∴ 625 = 49 + BC2
∴ BC2 = 625 – 49
∴ BC2 = 576
∴ BC = 24 cm .......[Taking square root of both sides]
∴ The length of the base of the given right angle triangle is 24 cm.
Concept: Right-angled Triangles and Pythagoras Property
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