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In a right angled triangle, if length of hypotenuse is 25 cm and height is 7 cm, then what is the length of its base?

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#### Solution

Let ∆ABC be the given right angled triangle.

AC = 25 cm, AB = 7 cm

In ∆ABC, ∠B = 90° ......[Given]

∴ AC^{2} = AB^{2} + BC^{2} .......[Pythagoras theorem]

∴ 25^{2} = 7^{2} + BC^{2}

∴ 625 = 49 + BC^{2}

∴ BC^{2} = 625 – 49

∴ BC^{2} = 576

∴ BC = 24 cm .......[Taking square root of both sides]

∴ The length of the base of the given right angle triangle is 24 cm.

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