In a reaction, 2A → Products, the concentration of A decreases from 0.5 mol L−1 to 0.4 mol L−1 in 10 minutes. Calculate the rate during this interval?
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Solution
Average rate = -`1/2 (triangle[A])/(trianglet)`
= - `1/2 ([A]_2- [A]_1)/(t_2-t_1)`
= -`1/2 (0.4-0.5)/10`
= -`1/2 (-0.1)/10`
= 0.005 mol L−1 min−1
= 5 × 10−3 M min−1
Concept: Rate of a Chemical Reaction
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