# In a parallel plate capacitor with air between the plates, each plate has an area of 6 × 10−3 m2 and the distance between the plates is 3 mm. Calculate the capacitance of the capacitor. - Physics

Numerical

In a parallel plate capacitor with air between the plates, each plate has an area of 6 × 10−3 m2 and the distance between the plates is 3 mm. Calculate the capacitance of the capacitor. If this capacitor is connected to a 100 V supply, what is the charge on each plate of the capacitor?

#### Solution

Area of each plate of the parallel plate capacitor, A = 6 × 10−3 m2

Distance between the plates, d = 3 mm = 3 × 10−3 m

Supply voltage, V = 100 V

Capacitance C of a parallel plate capacitor is given by,

"C" = (in_0"A")/"d"

Where,

in_0 = Permittivity of free space

= 8.854 × 10−12 N−1 m−2 C−2

∴ "C" = (8.854 xx 10^-12 xx 6 xx 10^-3)/(3 xx 10^-3)

= 17.71 xx 10^-12  "F"

= 17.71 pF

Potential V is related with the charge q and capacitance C as

"V" = "q"/"C"

∴ q = VC

= 100 xx 17.71 xx 10^-12

= 1.771 × 10−9 C

Therefore, the capacitance of the capacitor is 17.71 pF and the charge on each plate is 1.771 × 10−9 C.

Concept: The Parallel Plate Capacitor
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Chapter 2: Electrostatic Potential and Capacitance - Exercise [Page 86]

#### APPEARS IN

NCERT Physics Class 12
Chapter 2 Electrostatic Potential and Capacitance
Exercise | Q 2.8 | Page 86
NCERT Physics Class 12
Chapter 2 Electrostatic Potential and Capacitance
Exercise | Q 8 | Page 87
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