# In a group of students, there are 3 boys and 4 girls. Four students are to be selected at random from the group. Find the probability that either 3 boys and 1 girl or 3 girls and 1 boy are selected. - Mathematics and Statistics

Sum

In a group of students, there are 3 boys and 4 girls. Four students are to be selected at random from the group. Find the probability that either 3 boys and 1 girl or 3 girls and 1 boy are selected.

#### Solution

The group consists of 3 boys and 4 girls i.e., 7 students.
4 students can be selected from this group in ""^7"C"_4 = (7 xx 6 xx 5 xx 4)/(4 xx 3 xx 2 xx 1) = 35 ways
∴ n(S) = 35
Let A be the event that 3 boys and 1 girl are selected.
3 boys can be selected in 3C3 ways while a girl can be selected in 4C1ways.
∴ n(A) = ""^3"C"_3  xx ""^4"C"_1 = 4

∴ P(A) = ("n"("A"))/("n"("S")) = 4/35
Let B be the event that 3 girls and 1 boy are selected.
3 girls can be selected in 4C3 ways and a boy can be selected in 3C1 ways.
∴ n(B) = ""^3"C"_1 xx""^4"C"_3 = ""^3"C"_1 xx ""^4"C"_1 = 3 × 4 = 12

∴ P(B) = ("n"("B"))/("n"("S")) = 12/35
Since A and B are mutually exclusive and exhaustive events
∴ P(A ∩ B) = 0
∴ Required probability = P(A ∪ B)
= P(A) + P(B)

= 4/35 + 12/35

= 16/35