MCQ

In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?

#### Options

159

194

205

209

Advertisement Remove all ads

#### Solution

**209Explanation:**

We may have (1 boy and 3 girls) or (2 boys and 2 girls) or (3 boys and 1 girl) or (4 boys).

∴ Required number

= `(""^6C_1xx""^4C_3)+(""^6C_2xx""^4C_2)+(""^6C_3xx""^4C_1)+(""^6C_4)`

= `(6xx4)+((6xx5)/(2xx1)xx(4xx3)/(2xx1))+((6xx5xx4)/(3xx2xx1)xx4)+((6xx5)/(2xx1))`

= (24 + 90 + 80 + 15)

= 209

Concept: Permutation and Combination (Entrance Exam)

Is there an error in this question or solution?

Advertisement Remove all ads