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In a double-slit experiment using the light of wavelength 600 nm, the angular width of the fringe formed on a distant screen is 0.1°. Find the spacing between the two slits.? - Physics

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Numerical

In a double-slit experiment using the light of wavelength 600 nm, the angular width of the fringe formed on a distant screen is 0.1°. Find the spacing between the two slits.?

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Solution 1

Angular width (θ) of fringe in double-slit experiment is given by

`theta=lambda/"d"`

Where

d = Spacing between the slits

Given:

Wavelength of light, λ = 600 nm

Angular width of fringe

θ = 0.1° = `pi/1800` = 0.0018 rad

∴ d = `lambda/theta`

d = `(600xx10^(-9))/(18xx10^(-4))`

d = 0.33 × 103 m

Solution 2

Wavelength of light used, λ = 6000 nm = 600 × 10−9 m

Angular width of fringe, θ = 0.1° =` 0.1 xx pi/180 = 3.14/1800 "rad"`

Angular width of a fringe is related to slit spacing (d) as:

θ = `lambda/"d"`

`"d"= lambda/θ`

= `(600 xx 10^(-9))/(3.14 /1800)`

= 3.44 × 104 m

Therefore, the spacing between the slits is 3.44 × 104 m.

Concept: Interference of Light Waves and Young’S Experiment
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APPEARS IN

NCERT Class 12 Physics Textbook
Chapter 10 Wave Optics
Q 16 | Page 384
NCERT Physics Part 1 and 2 Class 12
Chapter 10 Wave Optics
Exercise | Q 10.16 | Page 384
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