Illustrate by taking examples of transition elements and non-transition elements that oxidation states of elements are largely based on electronic configuration. - Chemistry

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Short Note

Illustrate by taking examples of transition elements and non-transition elements that oxidation states of elements are largely based on electronic configuration.

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Solution

The electronic configuration of \[\ce{Cr}\] = 1s2 2s2 2p6 3s2 3p6 4s1 3d10

The electronic configuration of \[\ce{Cr}\] after losing one electron= 1s2 2s2 2p6 3s2 3p6 3d10

The electronic configuration of \[\ce{F}\] = 1s2 2s2 2p6 3s2 3p5

The electronic configuration of \[\ce{F}\] after gaining one electron= 1s2 2s2 2p6 3s2 3p6

From the above electronic configuration we can see that chromium will achieve stable electronic configuration after losing one 4s electron and fluorine will achieve stable electronic configuration after gaining one electron. So, the oxidation of chromium will be +1 and that of fluorine will be –1.

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Chapter 3: Classification of Elements and Periodicity in Properties - Multiple Choice Questions (Type - I) [Page 33]

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NCERT Exemplar Chemistry Class 11
Chapter 3 Classification of Elements and Periodicity in Properties
Multiple Choice Questions (Type - I) | Q 31 | Page 33

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