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If Zeba were younger by 5 years than what she really is, then the square of her age (in years) would have been 11 more than five times her actual age. What is her age now? - Mathematics

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Sum

If Zeba were younger by 5 years than what she really is, then the square of her age (in years) would have been 11 more than five times her actual age. What is her age now?

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Solution

Let Zeba’s age = x

(x – 5)2 = 11 + 5x

x2 + 25 – 10x = 11 + 5x

x2 – 15x + 14 = 0

x2 – 14x – x + 14 = 0

x(x – 14) – 1(x – 14) = 0

x = 1 or x = 14

We have to neglect 1 as 5 years younger than 1 cannot happen.

Therefore, Zeba’s present age = 14 years.

Concept: Nature of Roots
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APPEARS IN

NCERT Mathematics Exemplar Class 10
Chapter 4 Quadatric Euation
Exercise 4.4 | Q 5 | Page 42
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