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Sum
If z1 = 1 – 3i, z2 = – 4i, and z3 = 5, show that (z1 z2)z3 = z1(z2 z3)
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Solution
(z1 z2) z3 = [(1 – 3i)(– 4i)]5
= [– 4i + 12i2]5
= [– 12 – 4i]5
= – 60 – 20i ........(1)
z1(z2 z3) = (1 – 3i)[(– 4i)(5)]
= (– 20i + 60i2)
= – 20i – 60 .......(2)
From (1) and (2) we get
∴ (z1 z2)(z3) = z1(z2 z3)
Concept: Basic Algebraic Properties of Complex Numbers
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