Question

If y = 2 + log x, then show that xy₂ + y₁ = 0.

Answer 1

y = 2 + log x

`y_1 = 0 +1/x`

i.e., `y_1 = 1/x`

`therefore y_2 = - 1/x^2`

Now `xy_2 + y_1 = x(- 1/x^2) + 1/x = (-1)/x + 1/x = 0`