Question
If y =1-cosθ , x = 1-sinθ , then ` dy/dx at " "0 =pi/4` is ............
Solution
Ans. (A)
`dy/dx=sintheta`
`(dx)/(d theta)=-cos theta`
`dy/dx=((dy)/(d theta))/((dx)/(d theta))=-sintheta/costheta=-tan theta`
`therefore dy/dx=-1`
Is there an error in this question or solution?
APPEARS IN
Solution If y =1-cosθ , x = 1-sinθ , then dy/dx at 0 =π/4 is Concept: Derivatives of Functions in Parametric Forms.
