#### Question

If y =1-cosθ , x = 1-sinθ , then ` dy/dx at " "0 =pi/4` is ............

#### Solution

Ans. (A)

`dy/dx=sintheta`

`(dx)/(d theta)=-cos theta`

`dy/dx=((dy)/(d theta))/((dx)/(d theta))=-sintheta/costheta=-tan theta`

`therefore dy/dx=-1`

Is there an error in this question or solution?

#### APPEARS IN

Solution If y =1-cosθ , x = 1-sinθ , then dy/dx at 0 =π/4 is Concept: Derivatives of Functions in Parametric Forms.