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# If x3y3=x2-y2, Find dydx - Mathematics and Statistics

Sum

If "x"^3"y"^3 = "x"^2 - "y"^2, Find "dy"/"dx"

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#### Solution

"x"^3"y"^3 = "x"^2 - "y"^2

Differentiating both sides w.r.t. x, we get

"x"^3 "d"/"dx" "y"^3 + "y"^3 "d"/"dx" "x"^3 = "2x" - "2y" "dy"/"dx"

∴ "x"^3 (3"y"^2) "dy"/"dx" + "y"^3 (3"x"^2) = "2x" - "2y" "dy"/"dx"

∴ 3"x"^3"y"^2 "dy"/"dx" + "2y" "dy"/"dx" = "2x" - 3"x"^2"y"^2

∴ "y"(3"x"^3"y" + 2)"dy"/"dx" = "x"(2 - 3"xy"^3)

∴ "dy"/"dx" = ("x"(2 - 3"xy"^3))/("y"(3"x"^3"y" + 2))

∴ "dy"/"dx" = "x"/"y"((2 - 3"xy"^3)/(2 + 3"x"^3"y"))

Concept: Derivatives of Inverse Functions
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#### APPEARS IN

Balbharati Mathematics and Statistics 1 (Commerce) 12th Standard HSC Maharashtra State Board
Chapter 3 Differentiation
Miscellaneous Exercise 3 | Q 4.12 | Page 100
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