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MCQ

Solve the following question and mark the best possible option.

If x, y, z, w, s are natural number If x, y, z, w, s are natural numbers such that 12 < x < y < z < 40 < w < s < 50, how many values are possible for the set (x, y, z, w, s)

#### Options

`""^27"C"_3 xx ""^10"C"_2`

`""^27"C"_3 xx ""^9"C"_2`

`""^28"C"_3 xx ""^9"C"_2`

`""^27"P"_3 xx ""^9P_2`

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#### Solution

Since 12 < x < y < z < 40 < w < s < 50, there are 27 numbers between 12 & 40.

So, x, y, z can be chosen in `""^27C_3` ways. There are 9 numbers between 40 & 50.

W, s can be chosen in `""^9C_2` ways.

So, Ans. = `""^27C_3 xx ""^9C_2`

Concept: Permutation and Combination (Entrance Exam)

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