Answer 1

We have: x sin(90°-θ) cot (90°-θ)=cos (90°-θ) 

Here we have to find the value of x 

We have: ` x sin (90°-θ)= cos θ, cos (90°-θ)= sin θ , `

`cot (90°-θ)= tan θ,`

⇒ `x sin (90°-θ) cot (90°-θ)= cos (90°-θ)`  

⇒` x cos θ tan θ=sin θ`

⇒ `x cos θ xx sin θ/cos θ=sinθ` 

⇒ `x=1`