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If X Sin (90° − θ) Cot (90° − θ) = Cos (90° − θ), Then X = - Mathematics

MCQ

If x sin (90° − θ) cot (90° − θ) = cos (90° − θ), then x =

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Solution

We have: x sin(90°-θ) cot (90°-θ)=cos (90°-θ) 

Here we have to find the value of x 

We have: ` x sin (90°-θ)= cos θ, cos (90°-θ)= sin θ , `

`cot (90°-θ)= tan θ,`

⇒ `x sin (90°-θ) cot (90°-θ)= cos (90°-θ)`  

⇒` x cos θ tan θ=sin θ`

⇒ `x cos θ xx sin θ/cos θ=sinθ` 

⇒ `x=1`

  Is there an error in this question or solution?
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APPEARS IN

RD Sharma Class 10 Maths
Chapter 10 Trigonometric Ratios
Q 15 | Page 57
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