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# If X = 3 And Y = − 1, Find the Values of the Following Using in Identify: (9y2 − 4x2) (81y4 +36x2y2 + 16x4) - Mathematics

Answer in Brief

If x = 3 and y = − 1, find the values of the following using in identify:

(9y− 4x2) (81y4 +36x2y2 + 16x4)

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#### Solution

In the given problem, we have to find the value of equation using identity

(i) Given  (9y− 4x2) (81y4 +36x2y2 + 16x4)

We shall use the identity  (a- b) (a^2 + ab + b^2) = (a^3 - b^3)

We can rearrange the  (9y− 4x2) (81y4 +36x2y2 + 16x4)as

(9y^2 - 4x^2) ((9y^2)^2) + 9y^2 xx 4x^2 + (4x^2)^2)

= (9y^2)^3 - (4x^2)^3

 = (9y^2) xx (9y^2) xx (9y^2) + (4x^2) xx (4x^2) xx(4x^2)

= 729y^6 - 64x^6

Now substituting the value  x =,y = -1 in 729y^6 - 64x^6we get,

729y^6 - 64x^6

729(-1)^6 - 64(3)^6

729(1) - 64(729)

729 - 46656

=-45927

Hence the Product value of (9y− 4x2) (81y4 +36x2y2 + 16x4)is  =-45927.

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#### APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 4 Algebraic Identities
Exercise 4.4 | Q 2.1 | Page 24
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