#### Question

If x = -3 and x = 2/3 are solutions of quadratic equation mx^{2 }+ 7x + n = 0, find the values of m and n

#### Solution

`mx^2 + 7x + n = 0`

Put x = -3 in given equation

`m(-3)^2 + 7(-3) + n = 0`

`=> 9m - 21 + n = 0`

=> 9m + n = 21 ......(1)

Put `x = 2/3` in given equation

`m(2/3)^2 + 7(2/3) + n = 0`

`=> (4m)/9 + 14/3 + n = 0`

=> 4m + 9n = -42 .....(2)

solving these equation we get

m = 3 and n = -6

Is there an error in this question or solution?

Solution If X = -3 and X = 2/3 Are Solutions of Quadratic Equation Mx2 + 7x + N = 0, Find the Values of M and N Concept: Quadratic Equations.