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# If X-2 = 64, Then X1/3+X0 = - Mathematics

MCQ

If x-2 = 64, then x1/3+x0 =

#### Options

• 2

• 3

• 3/2

• 2/3

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#### Solution

We have to find the value of x^(1/3+ x^0) if  x^-2 = 64

Consider,

x^-2 = 2^6

1/x^2 = 2^6

Multiply  1/2on both sides of powers we get

1/x^(2 xx 1/2) = 2^(6x1/2)

1/x^(2 xx 1/2) = 2^(6x1/2)

1/x = 2^3

1/x = 8/ 1

By taking reciprocal on both sides we get,

1/8 = x

Substituting 1/8 in x^(1/3 + x^0)we get

= (1/8)^(1/3) + (1/8)^0

= (1/(2^3))^(1/3) + (1/8)^0

= 1/(2^(3xx 1/3)) +1

 = 1/2^1 + 1

=1/2 +1

By taking least common multiply we get

= 1/2 + (1 xx 2)/(1 xx 2)

 = 1/2 + 2/2

= (1+2)/2

= 3/2

Is there an error in this question or solution?
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#### APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 2 Exponents of Real Numbers
Q 10 | Page 30
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