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# If X = 2/3 And X = −3 Are the Roots of the Equation Ax2 + 7x + B = 0, Find the Values Of Aand B. - Mathematics

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#### Question

If x = 2/3 and x = −3 are the roots of the equation ax2 + 7x + b = 0, find the values of aand b.

#### Solution

We have been given that,

ax2 + 7x + b = 0, x = 2/3, x = -3

We have to find and b

Now, if x = 2/3 is a root of the equation, then it should satisfy the equation completely. Therefore we substitute x = 2/3 in the above equation. We get,

a(2/3)2 + 7(2/3) + b = 0

(4a + 42+9b)/9=0

a=(-9b-42)/4                  ......... (1)

Also, if x = -3 is a root of the equation, then it should satisfy the equation completely. Therefore we substitute x = -3 in the above equation. We get,

a(-3)2 + 7(-3) + b = 0

9a - 21 + b = 0                 ......... (2)

Now, we multiply equation (2) by 9 and then subtract equation (1) from it. So we have,

81a + 9b - 189 - 4a - 9b - 42 = 0

77a - 231 = 0

a = 231/77

a = 3

Now, put this value of ‘a’ in equation (2) in order to get the value of ‘b’. So,

9(3) + b - 21 = 0

27 + b - 21 = 0

b = 21 - 27

b = -6

Therefore, we have a = 3 and b = -6.

Is there an error in this question or solution?

#### APPEARS IN

RD Sharma Solution for Class 10 Maths (2018 (Latest))