Answer 1

x = 1 is the common roots given quadric equation are , ax² + ax + 2 = 0 and x² + x + b = 0

Then find the value of ab.

Here, ax² + ax + 2 = 0 ….. (1)

 x² + x + b = 0….. (2)

Putting the value of  x = 1in equation (2) we get

`1^2 + 1+b = 0`

         `2 + b = 0`

                  `  b = -2`

Now, putting the value of  x= 1 in equation (1) we get

`a + a + 2 = 0`

    ` 2a + 2 = 0`

             `a = (-2)/2`

               `=-1`

Then,  `ab = (-1) xx (-2)`

                = 2